Weekly Assessment 3 Math Prep 2 Homework Second Term 2026

Hello my students how are you two today we'll explain from the book performency and assessment in mathematics week number three lesson number one calculation and product we will solve questions about homework and class assessment and perform also okay homework question if the order + and 3 equal the order and minus one find the square root of power 2 - + / two. First step we have first equal first and second equal second. Then the first rejection + 5 5 equal 8 and the second rejection equal second rejection. The value of b= 4. + 5= 8. Then the value of will be equal 3. Now we can find square root of power 2 + power 2. Square root of power 2 3^2 is 9 and 4^ 2 is 16 square root of summation 25 square 25 should be five. This question number one question number two if number of element is product about the order and to five the number of element of minus 2 and y= + 2. What is the value of Listen, we know number of element in was minus 2 and the cartisian product between and it's meaning number of element of product by number of element of this information the product between and number of order of pairs by product cartisian and is five and number of element in was minus 2 and number of element in was + 2. We can solve five equal. We have two conject terms and -2 and two. We have construct first by first and second by second two subtract by four and then move4 here 5 + 4 is 9. Then k^ 4= 9. So the value of equal positive or negative square root of 9 square root of 9 equ= 3. And the value of will be equal positive or negative -3. Next question. If x= 56 and 2 and three and five can find the number between and and has three elements and zed has two elements. 3 * 2 = 6. This letter letter letter union cartisian product by intersection by we can find the union between and right all element in and 1 5 6 five with repeating and intersection by and intersection by five then the cartisian product will be one or five the first and second will be five and five and third six with five okay question number okay next question number four we have the solution about cartis number axis and won't find yx as the first projection will be only and second projection will be second projection 367. Now we can find description MB Y2 and the present aroggram Y2 it will be link by 3 6 and 7 cartisian product by itself the result will be first 3x3 and 3x 6 and 3x 7 next 6 by 3 6 by six and six by 7 and next seven with three, seven with six and seven with seven. Okay, we can draw our diagram about y2. Draw rectangle like this and put the element of in it. Element of was 3 six 7 three point here and six and seven and the image going from 3 to 6 and 3 to 7 like this 3 to 7 and 7 to 6 and 6 to 7 and then three with seven and seven was three 7 was itself six was itself three was itself Okay. And then letter here you want to find number of X2. has has here how many elements in One. 1^2= 1. 1^2= 1. Next question number five. Find cartisian by one represent it cartisian diagram. First cartisian with zed set of 1 5 6 cartisian with zed. Zed was 2 three and five. One was two and then one with three. One was five. Five was two. Five was three. Five was five. And then six is two. Six was three. Six was five. Okay. And then we can represent by cartesian diagram. Draw vertical and horizontal like this. intersection. First start and here. was one, five and six and was 2 3 5 2 3 and five. one with two and five and six. Okay, the image about Next question find union cartisian product by intersection by Now will solve the equation here little down. We have union cartisian product with intersection by First union between and zed. Write all element in and zed. 1 5 6 7 1 5 6 7 product between intersection by They are intersection at five. Five was repeating in two cities. Then you can complete to find the answer. We want to find the result. One was five, five was five, six was five, and seven was five. Okay, so this homework, next video will complete the explain weekly assessment number three. Okay, goodbye.